Question

50 pts 50 pts 50pts

prove that sin²x+cos²x=1 ​

Answer 1

Answer:

sin €= p/h

cos €=b/h

therefore,

sin^2x=p^2/h^2

cos^2x=b^2/h^2

sin^2 x+cos^2 x=p^2/h^2+b^2/h^2

1 =(p^2+b^2)/h^2

1 =h^2/h^2[using pythagoras theorem]

1 =1

Hence,proved....

Another method is knowing to take the derivative of

f(x) = sin^2(x) + cos^2(x)

f '(x) = 2 sin(x) cos(x) + 2 cos(x) (-sin(x))

= 2 sin(x) cos(x) - 2 cos(x) sin(x)

= 0

Since the derivative is zero everywhere the function must be a constant.

Take f(0) = sin^2(0) + cos^2(0) = 0 + 1 = 1

So

sin^2(x) + cos^2(x) = 1 everywhere.

Answer 2

Your equation :

prove that sin²x+cos²x=1

Answer :

It's Answer is in image

Hope it helps and mark it as brain list