- 50 two rupees coins are places one above the
other to form a right circular cylinder. If each
coin has radius 1.4 cm and thickness 0.3 cm,
find its total surface area.
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Answer:
144.32cm²
Step-by-step explanation:
radius=1.4 cm
thickness=height=0.3 cm
total surface area=curved surface area of 50 cylinders(coins)+areas of both circular ends
=(2πrh×50)+2×πr²=(2×22÷7×1.4×0.3×50)+(2×22÷7×1.4×1.4)
=132+12.32=144.32cm²
The total surface area is144.32cm².
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