Question

50/x^2-2x^2/81 factorise​

Answer 1

Answer:

$\frac{50}{x^2}-\frac{2x^2}{81}=2(\frac{5}{x}+\frac{x}{9})(\frac{5}{x}-\frac{x}{9})$

Step-by-step explanation:

Formula used:

$a^2-b^2=(a+b)(a-b)$

$\frac{50}{x^2}-\frac{2x^2}{81}\\\\=2[\frac{25}{x^2}-\frac{x^2}{81}]\\\\=2[(\frac{5}{x})^2-(\frac{x}{9})^2]\\\\=2(\frac{5}{x}+\frac{x}{9})(\frac{5}{x}-\frac{x}{9})$

Answer 2

The required value is $2(\dfrac{5}{x}-\dfrac{x}{9})(\dfrac{5}{x}+\dfrac{x}{9})$

Step-by-step explanation:

Since we have given that

$\dfrac{50}{x^2}-\dfrac{2x^2}{81}$

We need to factorise it:

Taking two common from the numerator:

$2(\dfrac{25}{x^2}-\dfrac{x^2}{81})\\\\=2(\dfrac{5^2}{x^2}-\dfrac{x^2}{9^2})\\\\=2(\dfrac{5}{x}+\dfrac{x}{9})(\dfrac{5}{x}-\dfrac{x}{9})$

Hence, the required value is $2(\dfrac{5}{x}-\dfrac{x}{9})(\dfrac{5}{x}+\dfrac{x}{9})$

# learn more:

Factorise x 2 -2x - 3

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