If the fifth term of an AP is zero, show that its 33rd term is four times its 12 th term
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we know that nth term of an a(n) = a + (n - 1) * d
a(5) = a + (5 - 1) * d
= a + 4d.
Given that 5th term of an AP is 0.
= > a + 4d = 0.
= > a = -4d -------- (1)
Now,
a(12) = a + (12 - 1) * d
= a + 11d
= -4d + 11d
= 7d.
a(33) = a + (33 - 1) * d
= a + 32d
= -4d + 32d
= 28d
= 4 * 7d
Therefore 33rd term is 4 times its 12th term.
Hope it helps!
siddhartharao77:
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