Question

500 families with 3 children each selected randomly . related data is
No of boys - 0 1 2 3
no of families- 40 230 175 55
find probability that family choosen has
1) one boy
2) at least one boy
3) at most 2 boys
4) at least 3 boys​

Answer 1

For 1 boy = 230/500

For at least 1 boy = (500-40)/500

=> 460/500

For at most 2 boys = 455/500

For at least 3 boys = 55/500

Calculation is all yours

Answer 2

Concept

The probability is the likeliness  of happening an event among all the events. The probability=number of events/number of outcomes.

Given

no. of families                no. of boys

40                                      0

230                                    1

175                                      2

55                                      3

To find

The probabilities:

1. one boy
2. at least one boy
3. at most 2 boys
4. at least 3 boys

Explanation

1. The probabilities that the families having only one boy=230/500.
2. The probabilities that the familes having at least one boy=460/500
3. The probabilities that the families having at least 2 boys are =445/500
4. The probabilities that the families having at least 3 boys =55/500

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