Question

500 gram of lead melts at its melting point by providing heat at the rate of 330 W. The time taken to complete this process is 7 minutes what is the specific latent heat of fusion of the metal

Answer 1

Answer:

277200 Joules/kg   MARK AS BRAINLIEST

Explanation:

Given,

mass = 500g = 0.5kg

Power of the heat supplying appliance is 330W.

P = 330W = 330 J$s^{-1}$  (Joules per second)

time = 7 minutes = 60*7 = 420 seconds (nice)

Q (total energy supplied for fusion) = P x t

Q = 330 x 420 = 138600 Joules

since, Heat energy = mL (mass x latent heat)

Latent heat of fusion = Heat energy/mass

                                   = 138600/0.5

                                   = 277200 Joules/kg

Latent heat of fusion = 2.772 x $10^{5}$ $Jkg^{-1}$