Question

Calculate potential energy in case of dipole having magnitude of each charge as 3×10 raise to power -6 . Charges are separated by a distance of 2000°A

Answer 1

Given :

Two equal charges having equal magnitude of 3×10‾⁶ C are separated by a distance of 2000A°.

To Find :

Potential energy of the system.

Solution :

❖ Electric potential energy is a scalar quantity. While finding its value, the value of various charges must be substituted with their proper sign.

Potential energy of the system of two point charges is given by

$\dag\:\underline{\boxed{\bf{\pink{U=\dfrac{kq_1q_2}{r}}}}}$

» k denotes constant

» r denotes distance b/w both charges

For dipole,

• q₁ = 3 × 10‾⁶ C
• q₂ = -3 × 10‾⁶ C

By substituting the given values;

$\sf:\implies\:U=\dfrac{(9\times 10^9)(3\times10^{-6})(-3\times10^{-6})}{2000\times10^{-10}}$

$\sf:\implies\:U=\dfrac{-81\times10^{-3}}{2\times10^{-7}}$

$\sf:\implies\:U=-40.5\times10^{-3+7}$

$:\implies\:\underline{\boxed{\bf{\gray{U=-40.5\times10^{4}\:J}}}}$