Math, asked by raiayush482, 1 year ago

500 men took Dip in a tank which is 80 m long ,50 M broad. what is the rise in water level if the average displacement of water by a man is 4 m^3?

Answers

Answered by Bhaavya1
9
actual is 80*50=4000m^3..
increase in volume=500*4=2000m^3
total volume=6000m^3
Answered by nilesh102
8

\textbf{\huge\underline{\underline\red{solution} : -  }} \\  \\ \bold{\underline\purple{here \: we \: know}} \\  \\  \red{1.} \bold \blue{ \: length  \: (l)\: of \: rectangle \: \: tank \: is \: 80 \: m .} \\ \red{2.} \bold \blue{ \: breadth  \:( b)\: of \: rectangle \: tank \: is \: 50 \: m.} \\ \red{3.} \bold \blue{ \: displacement \: of \: water \: by \: a \: one \: } \\  \bold \blue{person \: in \: a \: tank \: is \: 4 \:  {m}^{3} .} \\  \\ \underline \bold\red{so \:  \:displacement \: of \: water \: in \: a \: tank \: by \:} \\ \underline \bold\red{ 500 \: persons  }  =  \blue{500 \times 4 = 2000 \: }\bold\blue{ {m}^{3}  \:  \:  \:  \: ..(1)} \\  \\  \underline \bold \purple{let \: height \: of \: rectangular \: tank \: is \: h} \\  \\ \underline\bold\blue{to \: find \: volume \: of \: water \: in \: tank} \\  \\ \underline \bold \red{volume\: of \: rectangular \: tank \: } =  \bold \purple{ l\times  b\times h} \\  \\  \bold \red{v.o.r.t} =  \bold \purple{80 \times 50 \times h} \\  \\ \bold \red{v.o.r.t} =  \bold \purple{(4000 \times h \: \: )  {m}^{3} \:  \:  \: ..(2) } \\  \\    \underline\bold\blue{as \: we\: know} \\  \\  \underline\bold\purple{volume \: of \: raised \: water \: in \: rectangular } \\ \underline\bold\purple{tank \: is \: equal \: to \: displacement \: of \: water \: in } \\ \underline\bold\purple{ tank\: by \:500 \: person .} \\  \\ \underline\bold\red{hence} \\  \\ \bold\red{volume \: of \: raised \: water \: in \: rectangular } \\\bold\red{tank \:}  = \bold\purple{ displacement \: of \: water \: in } \\ \bold\purple{ tank\: by \:500 \: person .} \\  \\   =  > \bold \blue{4000 \times h} = \bold \blue{20} \\  \\  =  > \bold \blue{h} = \bold \blue{ \frac{2000}{4000}} = \bold \blue{ \frac{1}{2} } = \bold \blue{0.5 \: m} \\  \\   \underline \bold\red{Hence   \: \purple{0.5 \: m} \: level \: of \: water \: rise \: in \: tank.}

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