500 men took dip in a tank which is 80meterlong 50 meter broad .what is the rise in water levelif the average displacement of water by a men is 4cubic meter
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Answered by
6
the answer is .5m
process .....
area = 80*50
vol. displaced by one men = 4 cubic meter
vol. displaced by 500 men = 500 * 4 cubic meter
rise in water level = area * h = 500 * 4
h*80*50= 500*4
so h = 0.5m
process .....
area = 80*50
vol. displaced by one men = 4 cubic meter
vol. displaced by 500 men = 500 * 4 cubic meter
rise in water level = area * h = 500 * 4
h*80*50= 500*4
so h = 0.5m
Answered by
3
volume of cuboid = l×b×h
so, 80×50×h=500×0.04
4000h=20
h=20/4000
h=0.005m
rise of water level in he pond=0.5cm
so, 80×50×h=500×0.04
4000h=20
h=20/4000
h=0.005m
rise of water level in he pond=0.5cm
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