Chemistry, asked by mukul69092, 11 months ago

500 mL of 0.2 M acidic KMnO, solution is used to
oxidise So, to H, SO What weight of so, will be
oxidised if KMno, itself gets reduced to MnSO?
(1) 32g
(2) 160 g
(3) 16 g
(4) 6.49 7​

Answers

Answered by prashant0011
0

Answer:

Answer:−

Rounak had 13 pens with him and Rahul had 27 pens.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

Explanation:−

\text{\underline{\underline{\purple{Given :}}}}

Given :

Rounak had = 25

Rahul had = 25 pens

Rounak gave 12 pens to Rahul

\text{\underline{\underline{\purple{To Find :}}}}

To Find :

Number of Pens left with Rahul and Rounak.

\text{\underline{\underline{\purple{Solution :}}}}

Solution :

Rounak had 25 pens, he gave 12 pens to Rahul. To get the pens left with Rounak We need to subtract 12 from 25.

\longrightarrow⟶ 25 - 12

\longrightarrow⟶ 13

Rounak had 13 pens with him.

As 12 pens were given to Rahul, add 12 to the Number of Pens with Rahul.

\longrightarrow⟶ 25 + 12

\longrightarrow⟶ 37

Rahul had 37 pens.

\therefore∴ Rounak had 13 pens with him and Rahul had 27 pens.

Explanation:

Answer:−

Rounak had 13 pens with him and Rahul had 27 pens.

\mathfrak{\large{\underline{\underline{Explanation :-}}}}

Explanation:−

\text{\underline{\underline{\purple{Given :}}}}

Given :

Rounak had = 25

Rahul had = 25 pens

Rounak gave 12 pens to Rahul

\text{\underline{\underline{\purple{To Find :}}}}

To Find :

Number of Pens left with Rahul and Rounak.

\text{\underline{\underline{\purple{Solution :}}}}

Solution :

Rounak had 25 pens, he gave 12 pens to Rahul. To get the pens left with Rounak We need to subtract 12 from 25.

\longrightarrow⟶ 25 - 12

\longrightarrow⟶ 13

Rounak had 13 pens with him.

As 12 pens were given to Rahul, add 12 to the Number of Pens with Rahul.

\longrightarrow⟶ 25 + 12

\longrightarrow⟶ 37

Rahul had 37 pens.

\therefore∴ Rounak had 13 pens with him and Rahul had 27 pens.

Answered by Anudesigner
0

Answer:

Explanation:

SO

2

gas can readily decolourise acidified KMnO

4

solution. Acidified KMnO

4

oxidises SO

2

to H

2

SO

4

. KMnO

4

itself is reduced to MnO

2

.

2KMnO

4

+H

2

SO

4

→K

2

SO

4

+2MnSO

4

+3H

2

O+5[O]

SO

2

+[O]+H

2

O→H

2

SO

4

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