Math, asked by Anonymous, 2 months ago

500 ml of a certain gas at 30°C was cooled to -20°C by keeping the pressure constant. Find the contraction in volume.

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Answers

Answered by shubhashrees73

Answer ❤️

V = 500ml

T1= 30°C = 273+30

= 303 k

T2= -20°+273

= 253 k

hence,. V1/T1 = V2/T2

V2= 500×253/303

= 417 ml

hence, content = (500 - 417)

= 83 ml

hope help you

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Answered by maishukhan

Answer:

hi mate her the answer

Step-by-step explanation:

V=500ml

t1= 30°C=274+30 =300k

t2= -20°+273=253k

V1/ t1=V2/t2

V2=500+253/303

=417ml

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