Let
f(x)=2x−1 and g(x)=3x+1
Then
(f∘f∘f)(x)=
(g∘g∘g)(x)=
((f∘g)−(g∘f))(x)=
((f+g)∘(f−g))(x)=
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Answer:
3x+1
12x+12
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