Question

please heeeelp!!!!!!!!!!!!!!!!!!!!!!!!​

Answer 1

here,

base of triangle = 1.6 m

height of triangle = 1.6 m

radius of semicircle = 1.6/2 = 0.8 m

ar(figure)= ar(triangle) + ar(semicircle)

$= \frac{1}{2} \times base \times height \: + \frac{1}{2} \pi \times {r}^{2}$

$= \frac{1}{2} \times 1.6 \times 1.6 + \frac{1}{2} \pi \times 1.6 \times 1.6$

$= \frac{1}{2} \times 1.6 \times 1.6(1 + \pi)$

$= 0.8 \times 1.6(1 + \pi)$

$= 1.28(1 + \pi)$

$= 1.28 \times 4.14$

$= 5.23 \: {m}^{2}$