Question

. 500 mL of a gaseous hydrocarbon when burnt in
excess of O, gave 2.5 L of CO, and 3.0L of water
vapours under same conditions. Molecular formula
of the hydrocarbon is -...

........pls anyone answer​

Answer 1

Answer:

This is too simple dont worry

Answer 2

$\huge \mathfrak{Solutions:-}$

Hydrocarbon --------------> Co2 + H2O

O.5 lit. ----------------> 2.5 lit + 3 lit.

0.5 moles. -----------> 2.5 moles + 3 moles

1 mole. -------------> 5 moles. + 6 moles.

Moles of C in Co2 = 1 × moles of Co2

= 1 × 5 = 5.

Moles of H in H2O = 2 × moles of H20

= 2 × 6 = 12.

Since 1 mole of the compound contain 5 moles of C and 12 moles of H, the molecular formula of the hydrocarbon is C5H12.

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