Question

500 mL solution of hydrochloric acid is made by dissolving 3.65 gram HCl in distilled water. Q.1» What is the molarity of chloride ions in the solution? Q.2». What will be the molarity of the hydroxide ions in this solution?

Answer 1

Q1.ans. Which means that's the NoN.. Metal react with H2 Gas to produce corresponding acids.

Answer 2

Answer:- Molarity of chloride ions in the solution= 0.2M

molarity of hydroxide ions = $5\times 10^{-14}M$

Explanation: $Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is L}}$

Given mass of $HCl$ = 3.65g

Molar mass of $HCl$  = 36.5 g/mol

Volume = 500 ml = 0.5L

${\text {molarity of}HCl=\frac{3.65g}{36.5g/mol\times 0.5L}=0.2M$

$HCl\rightarrow H^++Cl^-$

As 1 mole of $HCl$ gives 1 mole of  $H^+$ and 1 mole of $Cl^-$. Thus 0.2 moles of $HCl$ gives 0.2 moles of  $H^+$ and 0.2 moles of $Cl^-$.

Also $[H^+][OH]^-=10^{-14}$

$[OH]^-=\frac{10^{-14}}{[0.2]}=5\times 10^{-14}M$