500 persons are taking a dip into a cuboidal pond which is 80 m long & 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04 m2?
Answers
1300m²= area
0.04× 500= 20
80+50= 130
== 500-130=370 m
Answer:
The rise in water level of the rectangular tank is 50 m = 0.5 cm
Step-by-step explanation:
Given :
Number of persons to dip in a rectangular tank = 500
Length of a rectangular tank (l) = 80 m
Breadth of the rectangular tank (b) = 50 m
Average displacement of water by 1 person = 0.04 m³
Volume of water displaced by 500 persons = 500 × 0.04 = 20 m³ ………….(1)
Let ‘h’ m be the height of the raised water .
Volume of the rectangular tank = length × breadth × height = lbh
= 80 × 50 × h m³ = 4000h m…… ……….(2)
Volume of the raised water in the rectangular tank is equal to the volume of water displaced by 500 persons.
Volume of the rectangular tank = Volume of water displaced by 500 persons
4000h = 20 m³
[From eq 1 & 2]
h = 20/4000 = 1/200 = 0.005 m = 0.5 cm
h = 0.005 m = 0.5 cm
Hence, The rise in water level of the rectangular tank is 0.005 m = 0.5 cm
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