5000 molecules are present in sample of dry hydrogen having a volume v at s.t.p.calculate the volume of nitrogen has ehich jas 2.5* molecules at s.y.p.
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20ml. -_+37_-3+_++4+_(3+5+384+_+3(_+$+8_+3+_+3(4+"+
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Answer:5*10⁴
Explanation:
5000 molecules of H2 =V
By avogadros law
5000 molecules of N2 =V
25 *10÷5000=5*10⁴
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