500g water and 100g of ice at 0c are in a calorimeter whose water equivalent is 40g
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Here, the energy released by the condensation of vapour is not sufficient to melt the whole ice. So, the amount of energy released by the water vapour, when it condensed and comes to 00C is,
E=(mvapour)(Lvapour)+(mvapour)(Svapour)×100⇒E=10×540+10×1×100⇒E=6400 cal
So, let m mass of the ice is m'. Therefore,
m'Lice=6400 ⇒m'=640080⇒m'=80 gm
Therefore, the total amount of water in the capillary tube is,
m0=500+80+10 ⇒m0=590 gm
E=(mvapour)(Lvapour)+(mvapour)(Svapour)×100⇒E=10×540+10×1×100⇒E=6400 cal
So, let m mass of the ice is m'. Therefore,
m'Lice=6400 ⇒m'=640080⇒m'=80 gm
Therefore, the total amount of water in the capillary tube is,
m0=500+80+10 ⇒m0=590 gm
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