Math, asked by trivediankita, 1 year ago

504 cones each of diameter 3.5cm and height 3 cm melted and recast into a metallic sphere. find the diameter of the sphere and hence find the total surface area of the sphere .(take pie=22/7

Answers

Answered by Mathexpert
467
diameter of cone = 3.5 cm and height = 3 cm

Volume of cone =  \frac{1}{3} * \pi * r^2 h

                =  \frac{1}{3} * \frac{22}{7} * \frac{3.5}{2} * \frac{3.5}{2} * 3
             =  \frac{77}{8}

Volume of 505 cones = 504 * 77/8 = 4851 cu cm
 
 These cones are melted and made into a sphere..

Volume of sphere = 4851 cu cm              

 \frac{4}{3} * \pi * r^3 = 4851

 \frac{4}{3} *  \frac{22}{7}  * r^3 = 4851


r³ = 1157.625

r = 10.5 cm

Diameter = 21 cm

Total surface area of sphere = 4 * π * r² 

TSA = 4 * 22/7 * 10.5 * 10.5 = 1386 sq cm



BhavyBhatnagar: diameter of cone = 3.5 cm and height = 3 cm

Volume of cone = \frac{1}{3} * \pi * r^2 h

= \frac{1}{3} * \frac{22}{7} * \frac{3.5}{2} * \frac{3.5}{2} * 3
= \frac{77}{8}

Volume of 505 cones = 504 * 77/8 = 4851 cu cm

These cones are melted and made into a sphere..

Volume of sphere = 4851 cu cm

\frac{4}{3} * \pi * r^3 = 4851

\frac{4}{3} * \frac{22}{7} * r^3 = 4851

r³ = 1157.625

r = 10.5 cm

Diameter = 21 cm2
Answered by Anonymous
161
height of cone = 3 cm 
diameter of cone = 3.5 cm or radius = 3.5/2

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