504and1188 using Euclid, s algorithm find the HCF
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Answered by
6
Heya dear
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°.° 1188 > 504
1188 = 504 × 2 + 180
540 = 180 × 2 + 144
180 = 144 × 1 + 36
144 = 36 × 4 + 0
now get that remainder is 0 and divider is 36
that's why HCF of 504 and 1188 is 36
thanks
===================================
====================================
°.° 1188 > 504
1188 = 504 × 2 + 180
540 = 180 × 2 + 144
180 = 144 × 1 + 36
144 = 36 × 4 + 0
now get that remainder is 0 and divider is 36
that's why HCF of 504 and 1188 is 36
thanks
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Answered by
1
1188= 2×504+ 180
504= 2×180 + 144
180= 144×1+ 36
144 = 4×36+0
36 is the HCF or GCD.
504= 2×180 + 144
180= 144×1+ 36
144 = 4×36+0
36 is the HCF or GCD.
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