Question

50gm of ice at -6°C is dropped into water of 0°C how many gram of water freezes?[specific heat capacity of water=1cal ,Latent heat of ice=80cal/gm]

[Note: Numerical required]​

Answer 1

Answer:

Since ice melted at 0 Celesius then the heat gained by ice (latent heat) will melt it so you should substitute in that law

Q=mlf ..where Q is the heat required to convert ice to water , m is the mass of ice and lf is the latent heat of fusion

Q=5∗80=400cal