50gr of Caco, is reacted with 7.3 gr of diluted HCl at constant pres-
sure and temperature. Calculate volume and mole of carbon dioxiode
which is formed in above chemical reaction.
Answers
Answer:
ρ
=
P
M
R
T
0.0847
g/L
=
760
torr
×
1
atm
760
torr
×
M
0.0821
L
atm/mol K
×
290
K
M
= 2.02 g/mol; therefore, the gas must be hydrogen (H2, 2.02 g/mol)
We must specify both the temperature and the pressure of a gas when calculating its density because the number of moles of a gas (and thus the mass of the gas) in a liter changes with temperature or pressure. Gas densities are often reported at STP.
Example 2
Empirical/Molecular Formula Problems Using the Ideal Gas Law and Density of a Gas
Cyclopropane, a gas once used with oxygen as a general anesthetic, is composed of 85.7% carbon and 14.3% hydrogen by mass. Find the empirical formula. If 1.56 g of cyclopropane occupies a volume of 1.00 L at 0.984 atm and 50 °C, what is the molecular formula for cyclopropane?
Solution
Strategy: First solve the empirical formula problem using methods discussed earlier. Assume 100 g and convert the percentage of each element into grams. Determine the number of moles of carbon and hydrogen in the 100-g sample of cyclopropane. Divide by the smallest number of moles to relate the number of moles of carbon to the number of moles of hydrogen. In the last step, realize that the smallest whole number ratio is the empirical formula:
85.7
g C
×
1
mol C
12.01
g C
=
7.136
mol C
7.136
7.136
=
1.00
mol C
14.3
g H
×
1
mol H
1.01
g H
=
14.158
mol H
14.158
7.136
=
1.98
mol H
Empirical formula is CH2 [empirical mass (EM) of 14.03 g/empirical unit].
Next, use the density equation related to the ideal gas law to determine the molar mass:
d
=
P
M
R
T
1.56
g
1.00
L
=
0.984
atm
×
M
0.0821
L atm/mol K
×
323
K
M
= 42.0 g/mol,
M
E
M
=
42.0
14.03
=
2.99
, so (3)(CH2) = C3H6 (molecular formula)
Check Your LearningAcetylene, a fuel used welding torches, is comprised of 92.3% C and 7.7% H by mass. Find the empirical formula. If 1.10 g of acetylene occupies of volume of 1.00 L at 1.15 atm and 59.5 °C, what is the molecular formula for acetylene?
Answer:
Empirical formula, CH; Molecular formula, C2H2
MOLAR MASS OF A GAS
Another useful application of the ideal gas law involves the determination of molar mass. By definition, the molar mass of a substance is the ratio of its mass in grams, m, to its amount in moles, n:
M
=
grams of substance
moles of substance
=
m
n
The ideal gas equation can be rearranged to isolate n:
n
=
P
V
R
T
and then combined with the molar mass equation to yield:
M
=
m
R
T
P
V
This equation can be used to derive the molar mass of a gas from measurements of its pressure, volume, temperature, and mass.
Explanation: