50gr of water at 20° c is mixed with 50gr of water at t° c. if final temperature is 30° c then final t° c?
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mass and c (heat capacity) are the same. take em as they are. let T= 30° (final temperature, given)
t1=20, and t2= t2 (as we have to find it)
now, mc (T - t1)= mc (t2 - T)
50 × c × (30-20) = 50× c × (t2- 30)
(50 and c get cancelled on the both sides)
so, 10 = t2 - 30
t2 = 40° ...} ans.
t1=20, and t2= t2 (as we have to find it)
now, mc (T - t1)= mc (t2 - T)
50 × c × (30-20) = 50× c × (t2- 30)
(50 and c get cancelled on the both sides)
so, 10 = t2 - 30
t2 = 40° ...} ans.
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