Question

50kg of nitrogen and 10kg of hydrogen are mixed to produce ammonia . calculate the ammonia formed and identify the limiting reagent in the production of ammonia

Answer 1

N2 + 3 H2  ----------> 2 NH3

moles of nitrogen = 50/28 = 25/14  = 1.78

moles of hydrogen = 10/2 = 5

1 mole N2 reacts with 3 moles H2 to give 2 moles NH3

1.78 mole N2 reacts with (1.78 * 3 = 5.34) moles H2 

Hence, Hydrogen is limiting reagent.

1 mole H2 will give (2/3) moles NH3

5 mole H2 will give (10/3) moles NH3

so, moles of ammonia formed = 10/3 = 3.33 mol

HOPE THIS HELP....

Answer 2

Answer:

hydrogen is limiting reagent.

Explanation:

explanation is attached.