Question

50mL of water was added drop wise to 50g of dry soil, kept on a filter paper in a funnel. The amount of water collected in the graduated cylinder below was found to be 40mL. Calculate the percentage of water absorbed by the soil.

Answer 1

Percentage of water obtained is (40/50)×100
= 80 %
therefore percentage of absorbed water =
= 100 – 80
= 20%.

Answer 2

Given:

Weight of the soil = 50g

Initial volume of water (U) = 50mL

Final volume of water (V) = 40mL

To find:

The percentage of water absorbed by the soil = ?

Formula to be used:

Percentage of water absorbed = $\frac{(U-V)}{50}\times 100$

Calculation:

Substituting the given values in the formula, it gives

Percentage of water absorbed = $\frac{(U-V)}{50}\times 100$

Percentage of water absorbed = $\frac{(50-40)}{50}\times 100$

Percentage of water absorbed = $\frac{10}{50}\times 100$

Percentage of water absorbed = 0.2 × 100

Percentage of water absorbed = 20

Conclusion:

The percentage of water absorbed by the soil is calculated as 20%.

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