Question

50p - 32(q - r)^2 factorise​

Answer 1

50p - 32(q-r)^2

=> 50p - 32(q^2 + r^2 - 2qr)   [ (a-b)^" = a^2 + b^2 - 2ab ]

=> 50p -32q^2 - 32r^2 + 64qr

Answer 2

Answer:

2[(5+4q-4r)(5-4q-4r)]

Step-by-step explanation:

50p-32(q-r)^2

2[25p-16(q-r)^2]

2[5^2-4^2(q-r)^2]

2[5^2-(4q-4r)^2]                    [ a^2-b^2=(a+b)(a-b)

2[(5+4q-4r)(5-4q-4r)]

Done!!!