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A real image 1 /5th the size of the object is formed at a distance of 18cm from the concave mirror. Calculate the focal length of the mirror.
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As the image is real the mirror has to be concave. Let its focal length be f. u and v both have to be negative according to the coordinate system sign convention. Also mod(v) = (1/5)*mod(u). We have
1/v + 1/u = 1/f or
= -1/18 -1/(5*18) = -6/90 = 1/f or f = -15 cm
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Answered by
1
As the image is real the mirror has to be concave. Let its focal length be f. u and v both have to be negative according to the coordinate system sign convention. Also mod(v) = (1/5)*mod(u). We have
1/v + 1/u = 1/f or
= -1/18 -1/(5*18) = -6/90 = 1/f or f = -15 cm
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