50points!!!!!!!!!help me with questions no. 12 ❤❤❤❤❤
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Answered by
6
(15).
According to Area theorem
If two triagles are similar then ratio of their area is equal to square of ratio of any pair of corresponding sides.
Area of ΔABC / Area of ΔPQR = (BC / QR)^2
81 / 144 = (BC / 6)^2
9 / 12 = BC / 6
BC = 6 × 9 / 12
BC = 4.5 cm
According to Area theorem
If two triagles are similar then ratio of their area is equal to square of ratio of any pair of corresponding sides.
Area of ΔABC / Area of ΔPQR = (BC / QR)^2
81 / 144 = (BC / 6)^2
9 / 12 = BC / 6
BC = 6 × 9 / 12
BC = 4.5 cm
cute100:
but I was asking about 12 u know...
Answered by
12
According to Area Theorem.
If two triangles are similar then ratio of their Area is equal to square of ratio of any pair of corresponding sides.
Area of ∆ ABC / Area of ∆ PQR = (BC / QR)²
84 /144 = (BC/6)²
9/12 = BC /16
BC = 9×9/12
BC = 4.5cm
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