51+52+53+........+100 = ?
Answers
Answered by
4
Answer is 2525
HOPE IT HELPS.....
HOPE IT HELPS.....
Anonymous:
Please post complete solution, don't just simply post direct sol.
but it has direct solution
How did u do that??
Have u used sum of nth term formula
Is ur last question to me?
But tell me in which Std u r? Because this formula was introduced to students of Std 10th
Frnd, i'm in 10th Std.
Ok
Yes i have used sum of nth term formula
Answered by
5
Hii!
n = 50
a = 51
d = 1
Sn = n/2 [ a + ( n - 1) d]
S(50) = 50/2 [ 51 + ( 51 - 1) 1]
= 25 ( 51 + 50 × 1)
= 25 ( 51 + 50)
= 25 × 101
= 2525
Therfore, 51+52+53+.....100= 2525.
I hope this helped you.
n = 50
a = 51
d = 1
Sn = n/2 [ a + ( n - 1) d]
S(50) = 50/2 [ 51 + ( 51 - 1) 1]
= 25 ( 51 + 50 × 1)
= 25 ( 51 + 50)
= 25 × 101
= 2525
Therfore, 51+52+53+.....100= 2525.
I hope this helped you.
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