(51 + 52 + 53 + ... + 100) = ?
hardik5571:
3775 is the ans
Answers
Answered by
3
Hey there mate !!
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The correct answer is
Answer= 3775
Solution:
Sn = (1 + 2 + 3 + ... + 50 + 51 + 52 + ... + 100) - (1 + 2 + 3 + ... + 50)
= 100 x (1 + 100) - 50 x (1 + 50)
2 2
= (50 x 101) - (25 x 51)
= (5050 - 1275)
= 3775.
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Answered by
3
Hey....!! HERE IS YOUR ANSWER....!!
WE CAN SOLVE THIS BY METHOD OF ARITHMETIC PROGRESSION.......
a=51 , d=1 , last term = 100
Tn = a+(n-1)×d
100 = 51 + n-1
100-50 =n
n= 50....
Sum = n/2(2a+(n-1)×d)
= 50/2(2×51 +(50-1)×1)
= 25(102+49)
= 25 × 151
= 3,775........ Answer........
HOPE IT'S HELP YOU A LOT....!!
@ujjwalusri
WE CAN SOLVE THIS BY METHOD OF ARITHMETIC PROGRESSION.......
a=51 , d=1 , last term = 100
Tn = a+(n-1)×d
100 = 51 + n-1
100-50 =n
n= 50....
Sum = n/2(2a+(n-1)×d)
= 50/2(2×51 +(50-1)×1)
= 25(102+49)
= 25 × 151
= 3,775........ Answer........
HOPE IT'S HELP YOU A LOT....!!
@ujjwalusri
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