Math, asked by puspanjalimishra, 11 months ago

(51 + 52 + 53 + ... + 100) = ?


hardik5571: 3775 is the ans

Answers

Answered by Anonymous
3

Hey there mate !!


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The correct answer is


Answer= 3775


Solution:


Sn = (1 + 2 + 3 + ... + 50 + 51 + 52 + ... + 100) - (1 + 2 + 3 + ... + 50)


= 100 x (1 + 100) - 50 x (1 + 50)

2 2

= (50 x 101) - (25 x 51)


= (5050 - 1275)


= 3775.


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Answered by ujjwalusri
3
Hey....!! HERE IS YOUR ANSWER....!!

WE CAN SOLVE THIS BY METHOD OF ARITHMETIC PROGRESSION.......

a=51 , d=1 , last term = 100

Tn = a+(n-1)×d
100 = 51 + n-1
100-50 =n
n= 50....

Sum = n/2(2a+(n-1)×d)
= 50/2(2×51 +(50-1)×1)
= 25(102+49)
= 25 × 151
= 3,775........ Answer........

HOPE IT'S HELP YOU A LOT....!!
@ujjwalusri
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