Question

51. Present population is 10,000. It increases by
10% during the 1st year and decreases 10%
during 2nd year. Find the population after 2
years?
Full process​

Answer 1

Answer:

initial populatio=10000

incr. on population in 1 st year=(10000×10)/100=1000

net population after 10% increasing= 10000+1000=11000

now,

10% population decreases so, 10% of 11000= (11000×10) /100=1100

now, net population= 11000-1100=9900

Answer 2

Answer = 9900

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