Question

51. To make 100 ml of 2.5 M Glucose solution,
grams of Glucose (C6H1206) is required
A) 36
B) 90
C) 45
D) 54​

Answer 1

Answer:

mass of glucose will be 45 g

Explanation:

No. of mole = molarity X volume in L

= 2.5 x 0.1 = 0.25 mole of glucose

Mass of glucose = mole x molecular mass

= 0.25 x 180 = 45 g.

Answer 2

Answer:

molarity = number of moles/ volume in litre

number of moles= given mass/ molecular mass

volume in litres= 100/1000

molecular mass of glucose is 180

$2.5 = (x \div 180) \times (1000 \div 100)$

$2.5 = (x \times 10) \div 180 \\ 2.5 = x \div 18 \\ x = 2.5 \times 18 \\ x = 45$