Question

52. If a man travels at a speed of 30 km/hr,
he reaches his destination 10 minutes
late and if he travels at a speed of
42 km/hr, he reaches his destination
10 minutes early. The distance trav-
elled is :
A) 36 km
B) 35 km
C) 40 km
D) 42 km
​

Answer 1

Answer:

answer:

Let the distance be x km.

Then, correct time at a speed of

30 km / h = x30 - 1060

Correct time at a speed of 42 km /h

= x42 + 1060

=> x30 - 1060 = x42 + 1060

=> x30 - x42 = 26

=> x(12)1260 = 26

=> 72 x = 1260 × 2

=> x = 1260×272 => x = 35 km

Explanation:

hope it helps