Question

52. The emf of the cell reaction
Ag/Ag (0.1M) || Ag (1M) Ag at 298 K is
(1) 0.0059 V
(2) 0.059 V
(3) 5.9 V
(4) 0.59 V​

Answer 1

It's too simple ,

E = E° - 0.59/n log ([1M] / [0.1M])

E° = 0

So ,

here n = 1

E = 0.59/1 log (10)

E = 0.59 V

Answered by an IIT JEE ASPIRANT and all India mathematics OLYMPIAD TOPPER in class 10th

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