Question

53.
( 1) 6.023x1040
2) 12.046X1
If the weight of 5.6 litre of gas at NTP is 11.Og the gas may be
1) Phosphine 2) Phosgene
3) Nitric oxide 4) Carbondioxide
5.6 litre of a gas weighs 60g. The vapour density of gas is
4) 240​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

Given that:-

The weight of 5.6 litres of gas NTP =11 grams

we know that

Volume occupied by one mole of gas=22.4 litres

Moles of gas =weight /Occupied Volume

=>Moles of gas =5.6/22.4

=>(56/10)/(224/10)

=>56/224

=>1/4

weight of 1/4 moles of gas =11 grams

Weight of 1 mole of gas =11×4=44 grams

molar mass of 44grams is Nitric Oxide(N2O)

2)we know that

we know that Volume occupied by one mole of gas=22.4 litres

gas=22.4 litresMoles of gas =weight /Occupied Volume

>Moles of gas =5.6/22.4

>Moles of gas =5.6/22.4=>(56/10)/(224/10)

>Moles of gas =5.6/22.4=>(56/10)/(224/10)=>56/224

>Moles of gas =5.6/22.4=>(56/10)/(224/10)=>56/224=>1/4

>Moles of gas =5.6/22.4=>(56/10)/(224/10)=>56/224=>1/4weight of 1/4 moles of gas =60grams

gramsWeight of 1 mole of gas =60×4=240 grams

gramsmolar mass=2 Vapour density

=>Vapour density =Molar mass/2

=>Vapour density =240/2=120

Answer=120