Physics, asked by nikshithainjamury, 3 months ago

53. A square coil 10^3 Wbm^-2 area is placed perpendicular to a uniform magnetic field of intensity
10-2 m². the magnetic flux through the coil is​

Answers

Answered by phantomdeluxe0
0

Explanation:

A=10

−2

m

2

B=10

3

Wb/m

2

.

ϕ=BA=10weber

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