Math, asked by aaryantiwari4u, 3 months ago

please help.me solve this one

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Answered by vanshsaharya

1

Answer:

ar(∆ABD)=75 cm^2

75=1/2*b*h

75=1/2*10*h

75=5h

h=15

height of triangle ACD =height of trapezium

ar(ABCD)=1/2*(sum of parallel sides)*height

ar(ABCD)=1/2*(10+18)*15

ar(ABCD=1/2*28*15

ar(ABCD)=14*15

ar(ABCD)=210cm square

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