Question

53. Extraction of chromium is done from chromite ore
(Feo-Cr 03) by using following steps
4Feo-Cr2O3 + 8Na CO2 + 702
—8Na, Croa + 2Fe2O3 + 8CO,
2Na, Cro+H2SO4 → Na2Cr2O, + Na, SO4 + H2O
Na, Cr,0, + 3C — Na,Cr,O. + 300
Na, Cr,O + H20 — Cr,0, + 2NaOH
Cr2O3 + 2A1 -> Al03 + 2Cr
If 0.2 mole of chromite ore is used initially and rest
of the reactants are in excess, then mole of
chromium formed will be
(1) 0.2
(2) 0.4
(3) 0.3
(4) 0.6
pla​

Answer 1

ANSWER

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Answer 2

Answer:

0.2 moles of chromium will form.

Explanation:

Since we know that the principle of atomic rule or the popularly known POAC rule will be valid for the above equations. Hence, the initial moles of the reactant will equal to the final moles of the product.

Hence for the first equation we will get 1/2 moles of Na2CrO4 again from the next equation we will get the Cr2O3 to be again 1/2 moles so, the last reaction Cr2O3 + 2A1 -> Al03 + 2Cr will have the moles of chromium to be 1 since by the use of POAC we get the stoichiometric coefficient to be 2 so the moles of chromium will be 1 hence, 0.2 moles of chromium ore is taken hence the moles of chromium will be 0.2*1 = 0.2 moles.