Question

53 g of na2co3 obtained from 44 g of co2 when treated with 40g of naoh then limiting reagent is​

Answer 1

• 53g of Na2CO3 obtainted from 44 g of CO2 when treated with 40g NaOH

   then limiting reagent can be

• Balanced chemical equation for the reaction is as followw:-

                2NaOH + CO2 ———>Na2CO3 + H2O

                   (40g).      (44g).              (53g)

• No of moles of NaOH = Given mass / Molar mass

                                     =40/40

                                    =1 mole

      No of moles of CO2=44/44

                                          =1 moles

      No of moles of Na2CO3= 53/106

                                     =1/2=0.5 mole

• As per chemical equation 1 mole of CO2 react  with 2 mole of NaOH to produce 1 mole of Na2CO3.
• As we obtain 0.5 mole of Na2CO3 So it requires 1 mole of NaOH and 0.5 mole of CO2 and as in above question we have sufficient amount.

Hence,There is No limiting agent and the reaction completed.

Answer 2

mark me as brainlist