Physics, asked by kirankumarkarnala, 4 months ago

53.
The acceleration of a particle in SHM is 0.8ms2, when its displacement is 0.2m.
Then frequency of its oscillation is

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Answered by divyabhaskar29

3

Answer:

a=w2x

.8=w2 × .2

w2 = 4

w= 2

w=2πf=2

f= 1/π

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