53gm Na2CO3 is present in 250 ml of a Na2CO3 solution. calculate gm per litre, normality and molarity of the solution.
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Explanation:
molecular mass of Na2Co3 = 106 g/mol
no.of moles of Na2CO3= 53/106=0.5 moles\
Molarity = n/v = 0.5/250 * 1000 = 2M
Normality = 53/106 * 2*1000/250 = 4N
[N-factor of Na2co3 = 2]
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