Math, asked by vishalgowda99, 3 months ago

prove that sin3x=3sinx-4sin³x

Answers

Answered by ItzDinu

5

$\huge \mathscr{\orange {\underline{\pink{\underline {★Answer★:-}}}}}$

sin3x = sin(2x+x)

= sin2xcosx+cos2xsinx

= 2sinxcosxcosx+(1−2sin²x)sinx

= 2sinx(1−sin²x)+sinx−2sin³x

= 3sinx−4sin³x

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