Question

53x-47y=118 & 47x-53y=82 by substitution method​

Answer 1

41x+53y=135------------ (1)

53x+41y=147-------------(2)

by elimination method,

multiply 41 in eq.(1) and multiply 53 in eq.(2),

(41x+53y=135)×41

(53x+41y=147)×53

1681x+2173y=5535

2809x+2173y=7791

- - -

__________________(by subtracting)

-1128x = -2256. (2173y-2173y cancelled)

x = -2256/-1128(- and - is cancelled

x = 2

put the value of x in eq. (2),

53x+41y=147

53×2+41y=147

106+41y=147

41y=147-106

41y=41

y=41/41

y=1

so the value of x=2

y=1

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Answer 2

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ANSWER.

====> 1

==> 54x - 47y = 118

==> 6xy = 118

==> xy = 118 / 6

answer = 118/6

====> 2

==> 47x - 53y = 82

==> -6xy = 82

==> xy = 82/6

answer = 82/6