Question

54. A train is running on a circular track of radius 1 km at the rate of 36 km per hour. Find the angle, to the nearest minute, through which it will turn in 30 seconds.

Answer 1

Answer:

Train turning angle =>  17 Deg. 11 Min.

Step-by-step explanation:

Hey Mate,

Total central angle of a circle = 360°

Circumference of track = C = 2πr

C = 2 x 22/7 x 1

C = 44/7 km

C = $\frac{44000}{7}$ m

Distance covers by Train => $36*\frac{5}{18}*30$

=>  300 meter in 30 sec.

Train turning angle

=> $\frac{300}{44000/7}*360$

=>  300 x 7 x $\frac{360}{44000}$

=>  17 Deg. 11 Min.

Answer 2

Answer:

Train turning angle => 17 Deg. 11 Min.

Step-by-step explanation:

Hey Mate,

Total central angle of a circle = 360°

Circumference of track = C = 2πr

C = 2 x 22/7 x 1

C = 44/7 km

C = \frac{44000}{7}

7

44000

m

Distance covers by Train => 36*\frac{5}{18}*3036∗

18

5

∗30

=> 300 meter in 30 sec.

Train turning angle

=> \frac{300}{44000/7}*360

44000/7

300

∗360

=> 300 x 7 x \frac{360}{44000}

44000

360

=> 17 Deg. 11 Min.