Question

540 g ice mixed with 540 g water at 80 degree celsius .What is final temperature

Answer 1

Answer:

0 degreee celcius

Explanation:

Q= m*Cp*(∆T) = 540* 1* 80 = 43200 cal. Heat released by water to reach from 80°C to 0°C = heat required by ice to melt into water at 0°C. So, the ice will melt to water and it's temperature will be 0°C. Hence, the final state would be water at 0°C