9g if anhydrous oxalic acid is dissolved in 100g water. Find molality
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Explanation:
Molality= no. of moles of solute/weight of solvent(kg)
no. of moles = mass/mol.mass
Oxalic Acid C2O4H2
Molar mass of oxalic acid is 12*2+16*4+2*1
24+64+2 = 90g
n=9/90 = 0.1moles
weight of solvent =100g= 0.1kg
Molality = 0.1/0.1 = 1m
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