Question

9g if anhydrous oxalic acid is dissolved in 100g water. Find molality

Answer 1

Explanation:

Molality= no. of moles of solute/weight of solvent(kg)

no. of moles = mass/mol.mass

Oxalic Acid C2O4H2

Molar mass of oxalic acid is 12*2+16*4+2*1

24+64+2 = 90g

n=9/90 = 0.1moles

weight of solvent =100g= 0.1kg

Molality = 0.1/0.1 = 1m