Question

540 g of ice at 0°C is mixed with 540 g of water at 80°C. The final temperature of mixture is(a) 0°C(b) 40°C(c) 80°C(d) less than 0°C

Answer 1

a) 0°C

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Answer 2

Answer:

(a) 0°C

Explanation:

Ice = 540g (Given)

Water = 540g (Given)

Latent heat of fusion = 80 cal/g (Given)

Heat capacity of water =1 cal/g/°c 

Heat capacity of ice =0.5 cal/g/°c 

In the mixing process the heat transfers from water at 80°c to saturated ice at 0°c till the thermodynamic equilibrium occurs. Since ice is saturated, thus it will absorb the heat in the form of latent heat to convert into water.

Let final temperature of the mixture is = T°c

Thus, energy balance equation, T°c = cooling of hot water from 80°c to final temp T°c

= (540×80) + {540×1×(T-0)} = {540×1×(80-T)}

= 540×T = -540×T

= 1080×T = 0

= T = 0

Thus, the final temperature of mixture is 0°C