55.
49. The wavelength of electron in the
first orbit of hydrogen atom is 'x'
.Then circumference of the 5th orbit
is
11 5x 2) 25x 3)12.5x 4) 16x
Answers
Answered by
0
Answer:
answer to your question is Sapat or option number 4 16x
Answered by
0
Answer:
The circumference of the 5 th orbit is 25x
Explanation
λ= h/my
λ α 1/V
λ α 1/V α n
λ1/λ2= N1/n2
x/λ2 = 1/5
λ2= 5x
circumference of 5th orbit = nλ
= 5×5x = 25x
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