Question

55. A round table cover has six equal designs as shown in the given figure. If the radius of the cover is 35 cm then find the total area of the design. [Use V3 = 1.732 and [CBSE 2009, '14] T = 3.14.]​

Answer 1

Step-by-step explanation:

OB=OC=28cm

Area of circle =πr2=722×28×28

=88×28

=2464cm2

Since, ABCDEF is a regular hexagon 

∴ΔOBC is an equilateral Δ

ar(ΔOBC)=43×28×28=339.08cm2

Area of 6 triangles =6×339.08=2034.48cm2

Area of shaded region = Area of circle - Area of 6.

=2464−2034.48=429.52cm2

Rate =0.35cm2

∴ Rate =0.35×429.52=Rs.150.33