Question

550 kilojoule per cycle work is done by 1 mole of ideal gas in a cyclic process the amount of heat absorbed by the system in one cycle is

Ans 550kJ why?

Answer 1

change in internal energy for cyclic process is zero.
del U+del W=Q
del u=0
del W=Q

Answer 2

Answer : The amount of heat absorbed by the system in one cycle is, 550 KJ

Explanation :

According to the First law of thermodynamics,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat absorbed or released

w = work done

As we know that the work done by the system is negative and work done on the system is positive. So, the work done by the system will be, -550 KJ

As we are given that the process is cyclic. So, the internal energy is equal to zero.

The formula become,

$q+w=0$

Now put the value of work in this formula, we get the amount of heat absorbed.

$q+(-550KJ)=0$

$q=550KJ$

Therefore, the amount of heat absorbed by the system in one cycle is, 550 KJ